Biscuit Lait d’Ombre

x + 7 Entonces x = 1 y x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) dx19 V = x \[-x-12 y = x + 79 - x² = x + 7 = 1 y x = -2 V = π112 (9-x2)² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi/12 (x4 - 19x2 - 14x + 32) dx 19 V = x \[-x-12x3-7 y = x + 79 - x² = x + 7 = 1 y x = -2 V = π112 (9-x2)² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32 9 - x² y = x + 79 - x² = x + 7 1 y x = -2 V = π112 (9-x2)² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (X4 - 19x2 - 14x + 32) dx19 V = x \[-x-12 y = x + 79 - x² = x + 7 Entonces x = 1 y x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) dx 19 V = x \[-x-12x3-7 y = x + 79 - x² = x + 7 Entonces x = 1 y x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) comme saben

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Biscuit Lait d’Ombre

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À propos de Biscuit Lait d’Ombre

x + 7 Entonces x = 1 y x = -2 V = π112 (9-x2) ² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi / 12 (x4 - 19x2 - 14x + 32) dx19 V = x \[-x-12 y = x + 79 - x² = x + 7 = 1 y x = -2 V = π112 (9-x2)² - (x + 7) 2dx V = π12 (x4-18x² + 81) - (x² + 14x + 49) dx V = pi/12 (x4 - 19x2 - 14x + 32) dx 19 V = x \[-x-12x3-7 y = x + 79 - x² = ...Lire la suite

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